A car with mass 1137 kg, moving at 17 m / s, strikes a(n) 2540 kg car at rest. If the two cars stick together, with what speed do they move?
elastic collision? hey, this is physics question, why do you post here?
didnt know this wasnt for physics . oops
but I know @IDKwut knows how to solve, let him help
where is he???
m1 v1 = m1 V1 + m2 V2 = (m1 + m2) V Plug and solve for V.
yup and v2 =0 so that it 's easy to solve, right?
in not to sure what to plug in where, this is new to me
O. I'll give you another hint: V = m1/(m1 + m2) v1 Where m1 = mass 1, m2 = mass 2 and v1 = final velocity. Try it out. :D
is the answer 0.007087
Please tell me how you got that.
m1-1137 m2-17 v1-2540
17 is not the second mass...
2540?
Well, that's a given since it is in your question post. m1 = 1137, m2 = 2540, and velocity is measured in m/s which is 17 m/s, now plug into the formula I gave you. :)
thank you so much.
43197 is the answer?
Tell me how you got that now. I want to see how you work the problem out.
\[V = \frac{ m1 }{ (m1+m2) } \times v1\] Order of operations? Shouldn't it be \[V = \frac{ m1 \times v1 }{ (m1 + m2)}\]
Follow order of operations do not multiply the bottom and divide
Don't give her/him the answer. It's pretty simple work to do.
They are the same thing as long as you follow the operations
Was not going to
Re-stated the formula that was given above and gave a guideline of how order of operations matters here especially if they are plugging numbers into a calculator
5.257
Good job! :)
thank you
are you able to help with this one A(n) 1090 N man stands in the middle of a frozen pond of radius 6 . 09 m. He is un- able to get to the other side because of a lack of friction between his shoes and the ice. To overcome this difficulty, he throws his 1 . 05 kg physics textbook horizontally toward the north shore, at a speed of 4 . 53 m / s. How long does it take him to reach the south shore?
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