Question

find inverse y=(3^x)/(2+3^x)

Answer 1

wow.... but solvable
step 1: switch the role of x and y
\[x = \dfrac{3^y}{2+3^y}\]
step2, solve for y

Answer 2

done

Answer 3

well yes u need to seperate y by itself though

Answer 4

i got that. how do u solve for "Y"???

Answer 5

mmmmhhhh.... I know just that, the leftover is your duty. and the sentence "I got that" sounds familiar to me, hehehe

Answer 6

you familiar wid logs and stuff ?

Answer 7

no im serious. i got that but i have questions for just the next step. & yes i am familiar

Answer 8

good, start by crossmultiplying

Answer 9

\[x = \dfrac{3^y}{2+3^y}\]
\[x(2+3^y) = 3^y\]
\[2x+x3^y = 3^y\]
\[2x= 3^y(1-x)\]
\[\dfrac{2x}{1-x}= 3^y\]

Answer 10

use ur log properties to separate y

Answer 11

do you know what log properties to use?

Answer 12

ok wait i think i got it. is it this?

Answer 13

nope

Answer 14

why?

Answer 15

continue the stuff of @rational
apply the equivalent of exponential and log

Answer 16

no... work through it again

Answer 17

thats really a crazy abusive way of using(inventing) log properties lol :P