If each resistor in the circuit shown is 5.0 Ω and the battery is 12.0 V, what does the first voltmeter (V1) read?
(Points : 1)
0.12 V
0.35 V
0.96 V
2.4 V
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (anonymous):
@hartnn @zepdrix @.Sam. Plllllzzzz help me with this question...i tried and keep getting a huge #...its due tomorrow and I need to get it done :( @Luigi0210 @iambatman @Preetha anyone?
hartnn (hartnn):
could you find the series current throught the circuit ?
OpenStudy (anonymous):
yes, I got 1.8, not sure if that is right though
hartnn (hartnn):
R2 || R3 = 5 || 5
Req = R1 + R2||R3 + R4
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
and current I = V/ Req
where V =12
so try again
hartnn (hartnn):
first tell us what u geot for Req
OpenStudy (anonymous):
12.5?
hartnn (hartnn):
yes
Req = 12.5
now find I
OpenStudy (anonymous):
0.96
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
yes, I = 0.96A
this currrent will flow through the parallel combination of R1 and R2
hartnn (hartnn):
i meant R2 and R3
so, the voltage across it will be
V1 = I times (R2||R3)
OpenStudy (anonymous):
is that 0.96 * (5/2) = 2.4?
hartnn (hartnn):
correct! :)
OpenStudy (anonymous):
aw yea :) awesome
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I have one more question that I needed help with. I would really appreciate if you could help me with it, but if not its ok :)
hartnn (hartnn):
sure, its ok :)
OpenStudy (anonymous):
ok, cool :) one sec
OpenStudy (anonymous):
For the circuit shown, what is the power dissipated by R3?
(Points : 1)
2.0 W
2.5 W
2.8 W
5.2 W
hartnn (hartnn):
could you find the voltage across R3 ?
use the exact same method we discussed above
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So, I find I first and then instead of using R2||R3, just R3? Does that work?
hartnn (hartnn):
why just R3 ? use R2||R3 only
its the same circuit , with numbers changed!
OpenStudy (anonymous):
oh, ok :) I will try
OpenStudy (anonymous):
i got 145.3...
hartnn (hartnn):
for what ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
for voltage
OpenStudy (anonymous):
but I think that might be wrong
hartnn (hartnn):
yeah try again
hartnn (hartnn):
Req = 8.5+3.2 + 13 || 18
I = 15/ Req
V_18 = I * (13||18)
OpenStudy (anonymous):
I keep getting 19.2 for I
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
Power dissipated = V_18 ^2/ 18
hartnn (hartnn):
Req = ... ?
OpenStudy (anonymous):
7.5
OpenStudy (anonymous):
1/13 + 1/18 = 1/R ---> 31/234 = 1/R ----> 234/31 = R...or am I making a mistake?
hartnn (hartnn):
thats just 13||18
Req is actually = 8.5+3.2 + 13 || 18
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So Req is 19.2
hartnn (hartnn):
and current I ?
OpenStudy (anonymous):
current = 0.78125-----but that gives me Power dissipated to be 5.9...which isn't an option
hartnn (hartnn):
how....
thats just the current through entire circuit, not through that resistor
hartnn (hartnn):
we need to find the voltage across the resistor
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh, ok, that makes sense
hartnn (hartnn):
V_18 = I * (13||18)
OpenStudy (anonymous):
i used your formula V_18^2/18 and got 1.93...is that the right thing?
hartnn (hartnn):
yeah, correct!
nearest option is 2
OpenStudy (anonymous):
ok :) awesome!!! Thank you SOOOO much for helping me :)
Still Need Help?
Join the QuestionCove community and study together with friends!