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Physics 20 Online
OpenStudy (anonymous):

If each resistor in the circuit shown is 5.0 Ω and the battery is 12.0 V, what does the first voltmeter (V1) read? (Points : 1) 0.12 V 0.35 V 0.96 V 2.4 V

OpenStudy (anonymous):

OpenStudy (anonymous):

@hartnn @zepdrix @.Sam. Plllllzzzz help me with this question...i tried and keep getting a huge #...its due tomorrow and I need to get it done :( @Luigi0210 @iambatman @Preetha anyone?

hartnn (hartnn):

could you find the series current throught the circuit ?

OpenStudy (anonymous):

yes, I got 1.8, not sure if that is right though

hartnn (hartnn):

R2 || R3 = 5 || 5 Req = R1 + R2||R3 + R4

hartnn (hartnn):

and current I = V/ Req where V =12 so try again

hartnn (hartnn):

first tell us what u geot for Req

OpenStudy (anonymous):

12.5?

hartnn (hartnn):

yes Req = 12.5 now find I

OpenStudy (anonymous):

0.96

hartnn (hartnn):

yes, I = 0.96A this currrent will flow through the parallel combination of R1 and R2

hartnn (hartnn):

i meant R2 and R3 so, the voltage across it will be V1 = I times (R2||R3)

OpenStudy (anonymous):

is that 0.96 * (5/2) = 2.4?

hartnn (hartnn):

correct! :)

OpenStudy (anonymous):

aw yea :) awesome

OpenStudy (anonymous):

I have one more question that I needed help with. I would really appreciate if you could help me with it, but if not its ok :)

hartnn (hartnn):

sure, its ok :)

OpenStudy (anonymous):

ok, cool :) one sec

OpenStudy (anonymous):

For the circuit shown, what is the power dissipated by R3? (Points : 1) 2.0 W 2.5 W 2.8 W 5.2 W

hartnn (hartnn):

could you find the voltage across R3 ? use the exact same method we discussed above

OpenStudy (anonymous):

So, I find I first and then instead of using R2||R3, just R3? Does that work?

hartnn (hartnn):

why just R3 ? use R2||R3 only its the same circuit , with numbers changed!

OpenStudy (anonymous):

oh, ok :) I will try

OpenStudy (anonymous):

i got 145.3...

hartnn (hartnn):

for what ?

OpenStudy (anonymous):

for voltage

OpenStudy (anonymous):

but I think that might be wrong

hartnn (hartnn):

yeah try again

hartnn (hartnn):

Req = 8.5+3.2 + 13 || 18 I = 15/ Req V_18 = I * (13||18)

OpenStudy (anonymous):

I keep getting 19.2 for I

hartnn (hartnn):

Power dissipated = V_18 ^2/ 18

hartnn (hartnn):

Req = ... ?

OpenStudy (anonymous):

7.5

OpenStudy (anonymous):

1/13 + 1/18 = 1/R ---> 31/234 = 1/R ----> 234/31 = R...or am I making a mistake?

hartnn (hartnn):

thats just 13||18 Req is actually = 8.5+3.2 + 13 || 18

OpenStudy (anonymous):

So Req is 19.2

hartnn (hartnn):

and current I ?

OpenStudy (anonymous):

current = 0.78125-----but that gives me Power dissipated to be 5.9...which isn't an option

hartnn (hartnn):

how.... thats just the current through entire circuit, not through that resistor

hartnn (hartnn):

we need to find the voltage across the resistor

OpenStudy (anonymous):

oh, ok, that makes sense

hartnn (hartnn):

V_18 = I * (13||18)

OpenStudy (anonymous):

i used your formula V_18^2/18 and got 1.93...is that the right thing?

hartnn (hartnn):

yeah, correct! nearest option is 2

OpenStudy (anonymous):

ok :) awesome!!! Thank you SOOOO much for helping me :)

hartnn (hartnn):

welcome ^_^

Directrix (directrix):

@Daniellelovee

OpenStudy (daniellelovee):

@Directrix

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