Question

What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g?



12.5%

55.6%

79.8%

87.9%

Answer 1

\[\color{green}{\begin{align*}\% \text{yield} &= \frac{\text{actual yield}}{\text{theoretical yield}} \times 100 \\ \\&= \frac{222.0~\text{g}}{275.6~\text{g}} \times 100 \\ &\text{etc.} \end{align*}}\]