√2x+1=√x+4
Start by taking the square root of both sides.
Since x√ is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. x√+4=2x−−√+1 Since 4 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 4 from both sides. x√=−4+2x−−√+1 Add 1 to −4 to get −3. x√=−3+2x−−√ To remove the radical on the left-hand side of the equation, square both sides of the equation. (x√)2=(−3+2x−−√)2 Simplify the left-hand side of the equation. x=(−3+2x−−√)2 Simplify the right-hand side of the equation. x=9−62x−−√+2x Since the radical is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. 9−62x−−√+2x=x Move all terms not containing 2x−−√ to the right-hand side of the equation. −62x−−√=−9−2x+x Simplify the right-hand side of the equation. −62x−−√=−x−9 To remove the radical on the left-hand side of the equation, square both sides of the equation. (−62x−−√)2=(−x−9)2 Simplify the left-hand side of the equation. (−6)2(2x)=(−x−9)2 Simplify the right-hand side of the equation. (−6)2(2x)=x2+18x+81 Squaring an expression is the same as multiplying the expression by itself 2 times. (−6)(−6)(2x)=x2+18x+81 Multiply to simplify the expression (−6)(−6). 36(2x)=x2+18x+81 Multiply 36 by each term inside the parentheses. 72x=x2+18x+81 Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. x2+18x+81=72x Since 72x contains the variable to solve for, move it to the left-hand side of the equation by subtracting 72x from both sides. x2+18x+81−72x=0 Since 18x and −72x are like terms, add −72x to 18x to get −54x. x2−54x+81=0 Use the standard form of the quadratic (ax2+bx+c) to find a,b, and c for this quadratic. a=1,b=−54,c=81 Use the quadratic formula to find the solutions. x=−b ± b2−4ac−−−−−−−√ 2a Substitute in the values of a=1,b=−54, and c=81. x=−(−54) ± (−54)2−4(1)(81)−−−−−−−−−−−−−−−√ 2(1) Multiply −1 by each term inside the parentheses. x=54 ± (−54)2−4(1)(81)−−−−−−−−−−−−−−−√ 2(1) Simplify the discriminant. x=54 ± 36 2√ 2(1) Simplify the denominator. x=12(54±362√) Solve the x=27+182√ Solve the − portion of ±,(54−36 2√ )(2). x=27−182√ The final answer is the combination of both solutions. x=27+182√,27−182√ Verify each of the solutions by substituting them back into the original equation 2x−−√+1=x√+4 and solving. In this case, the solution (27−182√) was proven to be invalid during this process. x=27+182√ x≈52.455844122716
is this multiple choice?
yes A) 3 B) 1/3 C) -3 d) 1
\(\sqrt{2x + 1} = \sqrt{x + 4}\) Start by squaring both sides to get: 2x + 1 = x + 4 Then solve for x
thank you!!
wait i am lost i did that and I got 1x=3???? what do i do next
1x means the same thing as x. So you have x=3
At that point, you can plug it in and check it.
okay thanks. sorry i am not that good at math
\(1 \times 2 = 2\) \(1 \times 3 = 3\) \(1 \times 4 = 4\) \(1 \times 5 = 5\) . . . \(1 \times x = x\)
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