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Mathematics 12 Online
OpenStudy (anonymous):

Given that w = ku + mv, prove algebraically that u X v * w = 0? k and m are scalars, u, v, and w are vectors. * is dot product. X is cross. Thanks

OpenStudy (loser66):

first off, I have to recall the properties of dot product and cross product we use to prove this problem. To dot product: \(\vec a\bullet \vec b= \vec b\bullet\vec a\) To cross product \((\vec a +\vec b)\otimes \vec c = \vec a\otimes \vec c +\vec b\otimes \vec c\) To combination: \(\vec c \bullet (\vec a\otimes \vec b) = (\vec c\otimes \vec a)\bullet vec b\) Now, apply \((\vec u\otimes \vec v)\bullet \vec w = \vec w\bullet (\vec u \otimes \vec v)\)=\((\vec w\otimes \vec u )\bullet \vec v\) Replace \(\vec w = k\vec u+m\vec v\) \(( (k\vec u +m\vec v)\otimes \vec u))\bullet \vec v\) \(=((k\vec u\otimes \vec u)+(m\vec v\otimes \vec u))\bullet \vec v\) the frist term =0.(I think you know why) so, it becomes \((m\vec v\otimes \vec u)\bullet \vec v\)=\(\vec v \bullet(m\vec v\otimes \vec u)\) \(= (\vec v\otimes m\vec v)\bullet \vec u\) \(=0\bullet \vec u =0\)

OpenStudy (anonymous):

Thank you so much :)

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