Question

create a quadratic function with two real zeros

Answer 1

y=(x-a) (x-b) (x-c)
This is not a quadratic but you should be able to easily determine the zeros and the degree.
The zeros are a, b, and c
Degree is three
You should be able to make a function now that is degree 2 and has 3 zeros

Answer 2

Two not three zeros

Answer 3

I'm not good at this :(

Answer 4

It is not hard. You can do it. Just make it to where has two distinct zeros with degree two.

Answer 5

Can you tell me what you don't understand in my example?

Answer 6

is 0=x^2+4x+1
one?
@freckles

Answer 7

Well y=x^2+4x+1 or even y=x^2+4x

I was saying earlier you need a degree 2 poly with two distinct zeros such as y=(x-a) (x-b) where you get to choose any real numbers for a and b but you must choose them diffeewbtly
If you wanted in expanded form it would be
y=x^2-(a+b)x+ab
So if you chosen a to be 2 and b to be 1. That would give y=x^2-(2+1)x+(2)(1)
Simplfyinh gives
y=x^2-3x+2
Now yours I knew that would work because b^2-4ac was greater than zero