Question

find the inverse of each function. then graph the function and its inverse. g(x)=2x^2-3

Answer 1

Switch x and y, then solve for y again.
So \(\Large y=2x^2-3 ======> x=2y^2-3\)

Answer 2

how do you graph it?

Answer 3

Do you have the inverse equation?

Answer 4

is it y=i sq root 2x+6/2?

Answer 5

I don't think you need an i there.

\(\Large f^{-1}(x)=\sqrt{\frac{x+3}{2}}\)

Answer 6

so how'd u graph it?

Answer 7

You can just plot in random x-coordinates and get out a y-coordinate. Here's what it would look like:

Answer 8

what about if its a fraction--> -2/3x

Answer 9

\(\Large -\frac{2}{3x}\) or \(\Large -\frac{2}{3}x\)?

Answer 10

the second one

Answer 11

It's the same as \(\Large -\frac{2x}{3}\) Just multiply.
So say you had \(x=3\) you plug that in \(\Large -\frac{2}{3}*3\)
The 3 cancels, and you are left with -2.

Or if you had 2. \(\Large -\frac{2}{3}*2\) It would be \(\Large -\frac{4}{3}\).

Answer 12

what would be the inverse of the equation pls?

Answer 13

Here are some steps that'll help you,

To find the inverse:

Replace f(x) with y
Switch x's and y's, so put x where y is and x where y is.
Solve for y
Replace y with f^-1(x)

Answer 14

Oh, inverse?
\(\Large y=-\frac{2x}{3}===> x=-\frac{2y}{3}\)
Solve for y by multiplying by 3, the dividing:
\(\Large -\frac{3x}{2}=f^{-1}(x)\)