Chem question!! please ppl explain to me this tiny question :3
here it is the answer is C but i don't get why
@emcrazy14 @Kainui @aaronq
strong acid will convert alcohols to alkenes, then the excess strong acid is neutralized by the strong base
@JFraser so conc H2SO4 is taking H2O out from alcohol thus forming alkene but i don't get the part about dilute NaOH
when all the alcohol has been added, there is still some leftover H2SO4. to purify the alkene, the leftover H2SO4 must be neutralized. that's why NaOH is added as the second step
@JFraser but why is it dilute? not concentrated could you please tell me what does reagent dil NaOH usually do to the compound and what does concentrated NaOH does?
if you add concentrated NaOH, you run the risk of having an excess of NaOH left over, which you'd have to neutralize with more strong acid. using a dilute solution means you can be more careful in neutralizing the excess acid
@JFraser i don't mean in this reaction, i just mean in general
concentrated NaOH with concentrated H2SO4 will also release a lot of heat, so dilute is safer for that reason. i'm not sure what concentrated NaOH will do to the alkene, i forget that part
I just have a little doubt that I want to clear out So does that mean when it comes to turning alcohols to alkene; acids are not the only reagent?
the NaOH isn't used to dehdydrate the alcohol, the NaOH is used to neutralize the excess acid
Coz Its written in my book that powdered Al2O3 is used in dehydration of alcohol to alkene
i'm sure it can be. it acts as an oxidizing agent
Oh ok thank you sir
ohhh ok i get it now so as purification they mean neutralization of excess acid left out after forming alkene @JFraser
yes
owkkk thank you so much :* @JFraser
YW
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