FLASH CARDS Is this the only diagonal in this concave hexagon?
@ganeshie8
@navk
You can draw more diagonals in it by joining vertices which are not adjacent
Would this be too much? does it make sense?
they are okay as long as you do not join two adjacent vertices to form a diagonal, which would result in over writing a side of the polynomial anyhow.. although I'm unsure whether the diagonal can go out of the polynomial or not (in case of concave polynomials)
Edit: Yes you can have diagonals that go outside the polynomial as well
Ok. and can i ask you a few more questions?
np
The third point has to make this an isosceles right triangle and no matter how much i try i cant get it right
Do you have to solve this question on paper with the help of a compass or with calculator?
Nop no calculator involved. But it doesnt say so i guess mayb i compass would work
but i wouldnt know how to use a compass on this problem
Take a compass and set it to a specific length, preferably shorter than the 7 units line given in the diagram. Set it, turn by turn, on each end of the line and draw an arc with it. The two arcs will intersect at a point. This point completes an isosceles triangle, but not necessarily a right angled triangle. For getting a right angled triangle, increase or decrease the length of the compass and check with the pythagorean theorem
omg there is an extremely simpler way to do that, as compared to the one I described above
EM is 7 units in length. let it be one leg of the isosceles triangle, and the other leg should have 7 units length too. further, since it is a right triangle, the two legs of the isosceles trianlge should be at 90 degrees to each other. So from point E or M just take a 7 unit line perpnedicular to EM
this will give you the two of the points you need: (3, 4) and (3, -3)
Sorry i didnt ever reply OS was losing connection with me
thats okay the same was happening on my browser
can you help me with some geometry flashcards? like for example this one idk what to say about it
The three lines are the angle bisectors of the triangle, and they meet at point P. P thus becomes the in center of the triangle
and i can also say that it has three pairs of congruent acute angles and that must be all there is to say
How about this one? I think its trying to ask how would i solve for x? but i dont know
The question, from the diagram, seems to be "Find the measure of an internal angle of a regular pentagon."
would it be 180(n-2) or 180(n-2) divided by 2?
use the formula for sum of interior angles of a polygon 180(n - 2) to find the total sum of the angles then, since it is given that the pentagon is regular, which means that its sides are equal, and consequently its angles as well, so divide the total sum by 5 to get the measure of each angle. this is really simple
But since there is no numbers do i actually try to solve or just write an explanation?
There is only one number you need to solve the problem, the number of sides in the regular polygon which is given by 'n' in the formula
so you do need to solve it using that formula
Kay i got it. 108 degrees
These are called consecutive interior angles right ?
Yes and also co-interior angles
For this one im really confused
It is an identity: x is twice of y btw please post the in a new question :) .. the scrolling down becomes quite hard!
Lol sorry I will
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