What is the final balance for the investment? $50,000 for 3 years at 3% compounded annually
Don't you just multiply them all otgether?
do u know the answer or no
\(\bf Balance=P\left(1+\frac{r}{n}\right)^{nt} \\ \quad \\ P=principal(\textit{original amount})\to 5,000\\ n=(\textit{number of times per cycle, annually, thus once a year})\to 1\\ r=rate\to 3\%\to \frac{3}{100}\to 0.03\\ t=years\to 3 \\ \quad \\ Balance=5,000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\)
still don't get it
hmm you may want to brush up your "compound interest" formula section
hmm actually the original amount is 50,000... anyow.. well... same just plug that in the compound interest formula \(\bf Balance=P\left(1+\frac{r}{n}\right)^{nt} \\ \quad \\ P=principal(\textit{original amount})\to 50,000\\ n=(\textit{number of times per cycle, annually, thus once a year})\to 1\\ r=rate\to 3\%\to \frac{3}{100}\to 0.03\\ t=years\to 3 \\ \quad \\ Balance=50,000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\)
so the answer will be
@jdoe0001 so the answer will what
plug in your values and get the balance
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