I will give a medal! What is the area of this composite figure?
Lets break this down. We know that there are two circles and one square. Do you know how to find the area of a square and a circle?
yes circle is A=pi*r to the second power square iis A=h to the second power
Okay. Now use these formulas to figure out the area. But remember that there are two semicircles.
well how?
You want to replace the numbers into the formula.
well there is only two numbers?
For example, we are to look at the square and figure out the area for that one. So we know that the formula would be: \[A=s^2\] Where s means the side. We also know that the side length of the square is 2. So we can also replace s for 2. \[A=2^2\] That makes our area be equal to: \[A=2\times2 = 4\] So our area for the square is 2. Now that is what you can do for the two circles also.
Sorry I meant that the area is actually 4 inches for the square.
well the two halfs make one circle right?
Sure
so the diameter is 2 in right?
Yes
so then we find the area of the circle and add it to the square
Try it out.
thnx it worked
You're welcome :)
can you help me with one more quistion?
Okay.
Use the Pythagorean theorem to find the missing length in the following right triangle.
Do you know what is the Pythagorean Theorem?
Meaning the formula?
no we went over it but i forgot what it is
It is: \[a^2+b^2=c^2\]
Do you understand this?
kinda but what is a b and c?
b is a variable that stands for one of the legs of the right triangle. c is the variable that stands for the hypotenuse (the longest side of the right triangle)
so c is the number 50? and b is the number 48?
Correct. However, remember that you're solving for a. Do you know how to do that?
Here's an easy way with the Pythagorean Theorem: \[a^2+48^2=50^2\] Square the numbers and then solve for a.
well for 48 squred i got 2,304 and for 50 squred i got 2,500 what do i do next?
Now you do: \[a^2+2,304=2,500\]
how do i find a?
Solve for a^2
sorry i actually forgot the simplest !
how do i know what is a?
Well you know that to solve for a, you have to do the inverse operation. |dw:1400724045661:dw|
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