Question

MEDAL WILL BE REWARDED:A ball is thrown upward. its height ( h, in feet ) is modeled by the function h = -16t^2 + 64t+3, where t is the length of time ( in seconds ) that the ball has been in the air. what is the maximum height the ball reaches?

Answer 1

Have you considered \(\dfrac{-64}{2(-16)}\)? aka -b/(2a)

Have you considered Completing the Square?

Answer 2

no

Answer 3

Oh, well, why don't you do that!?

Answer 4

the answer i got was 2 and thats not an answer choice. answer choices are : 3, 51,63,67

Answer 5

Yes, the maximum value occurs at \(t = 2\)

Answer 6

to get the maximum height,
evaluate the given height function at \(t = 2\)

Answer 7

how?

Answer 8

h = -16t^2 + 64t+3

Answer 9

plugin t = 2 above^

Answer 10

okay one second

Answer 11

i dont understand.

Answer 12

where do i plug the 2 in

Answer 13

h = -16t^2 + 64t+3

plugin t = 2, you get :

h = -16*2^2 + 64*2 +3

Answer 14

simplify

Answer 15

i did. its a huge number

Answer 16

http://www.wolframalpha.com/input/?i=+-16*2%5E2+%2B+64*2+%2B3

Answer 17

i got 643?

Answer 18

you should get 67

Answer 19

what did i do wrong

Answer 20

not sure, check that wolfram link...