Question

how to get from the first limit to the second one?

Answer 1

\[\frac{\dfrac{1}{x}}{-nx^{-n-1}}=\frac{\dfrac{1}{x}}{-nx^{-n}\dfrac{1}{x}}=\frac{1}{-nx^{-n}}=\frac{-x^n}{n}\]

Answer 2

I see, thank you!