Question

Logarithms

Answer 1

f(x) = log(x^2)
g(x) = 2logx

I think f(x) is not equal to g(x)
Is it correct

Answer 2

@skullpatrol

Answer 3

It came in some IIT paper

Answer 4

nope f(x) is equal to log x
becuse
\[\log(x ^{a})=a*\log(x)\]

Answer 5

it is equal,cuz log m ^n=n log m

Answer 6

Logarithm of negative numbers isn't defined

Answer 7

No but f(x) is defined for both positive and negative values of x
You square a negative u get positive
But g(x) only defined for "ONLY" positive values for x

Answer 8

Can we think about it that way

Answer 9

@sidsiddhartha @aaryaancoool

Answer 10

@skullpatrol

Answer 11

no....according to me.......

Answer 12

Equal or not equal

Answer 13

it is absolutely equal

Answer 14

I think it is not because
f(x) is defined for both positive and negative values of x
You square a negative u get positive
But g(x) only defined for "ONLY" positive values for x

Answer 15

I know that property

Answer 16

correct....but not for negative values because argument is always greater than 0(argument>0)

Answer 17

\[\large \bf \log_{10}-2=~ ~is~NOT~possible\]

Answer 18

Yes that's what i am saying so they are not equal
You square a negative you still get positive
Note that they are functions