Dissolved in water would sugars glucose and fructose constitute an equilibrium by the equation: glucose(aq) fruktose(aq) A chemist prepared one 0.244M fructose solution at 25 degrees C. At equilibrium, it was found that the concentration of fructose was decreased to 0.113M. a) Calculate from the data given equilibrium constant (Kc) for the reaction at 25 degrees C. b) At equilibrium, the percentage of fructose has been converted into glucose? ---------------- I would like to learn this, so any answer that help me learn how to solve this myself would be much appreciated!

Question

Dissolved in water would sugars glucose and fructose constitute an equilibrium by the equation:
glucose(aq) <=> fruktose(aq)

A chemist prepared one 0.244M fructose solution at 25 degrees C. At equilibrium, it was found that the concentration of fructose was decreased to 0.113M.

a) Calculate from the data given equilibrium constant (Kc) for the reaction at 25 degrees C.

b) At equilibrium, the percentage of fructose has been converted into glucose?

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I would like to learn this, so any answer that help me learn how to solve this myself would be much appreciated!

anonymous · Answer

The equilibrium constant formula is the following K=(product concentration in mol by liters)/(reagent concentration in mol by liters)
To calculate the percentage, use the data, calculate the difference between the concentration at the beginning and after the equilibrium was reached.
Don't forget that the volume of the solution won't change so you can find the amount of substance and deduce the percentage from the variation of the concentration.

anonymous · Answer

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