Question

Solve the following system of equations by substitution.
3y = 12
2x + y = -16
A. (-4, -10)
B. (-10, 4)
C. (4, 10)
D. (3, 3)

Answer 1

@Uri would you mind to help me??

Answer 2

@johnweldon1993 would you mind to help me??

Answer 3

@texaschic101 would you mind to help me?

Answer 4

@tanya123 would you mind to help me?

Answer 5

3y = 12 -- divide both sides by 3
y = 4
now sub 4 in for y in the other equation to find x
2x + y = -16
2x + 4 = -16
2x = -16 - 4
2x = - 20
x = -10
now sub -10 in for x
2(-10) + y = -16
-20 + y = -16
y = -16 + 20
y = 4

solution is : (-10,4)

Answer 6

Thanks!!! =)