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Trigonometry
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\[\begin{align*}P\left(1950<X<2050\right)&=P\left(\frac{1950-1975}{25}<\frac{X-1975}{25}<\frac{2050-1975}{25}\right)\\ &=P(-1<Z<3) \end{align*}\]
yeah
sure
Are the points (1,10), (2,5), and (4,1.25)?
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Fourth choice. When \(n=1\), the first term in the sequence is \[a_1=10\left(\frac{1}{2}\right)^{1-1}=10\] The average rate of change over 0 to 2 is \[\frac{a_2-a_0}{2-0}=\frac{5-20}{2-0}=-\frac{15}{2}\]
is your rate of change going to be + or - ?
by visual: we go from 10 to 1.25 ..... so we are dropping, average rate is slowing down, or negative
since 1,10 is a point, then a1 = k(..)^0 = k
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