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OpenStudy (anonymous):
OpenStudy (anonymous):
@Loser66 @mathstudent55
OpenStudy (loser66):
a) apply formula of midpoint
b) apply distance formula of one of the point and the midpoint
c) after having the radius and the midpoint, apply all in the equation of the circle
About what are the formulas: Google
OpenStudy (anonymous):
Thank You!!!!!!
OpenStudy (anonymous):
For B, once I have the answer of the distance formula do I att the answer to the midpoint or? @Loser66
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OpenStudy (anonymous):
Or do I divide the answer by two because the distance formula would make the diameter?
OpenStudy (loser66):
show me your work, I can check and correct the mistake (if there is some)
OpenStudy (loser66):
Re-read my instruction, I said: b) apply distance formula of one of the point and the \(\color{red}{midpoint}\)
OpenStudy (loser66):
not 2 given points
OpenStudy (loser66):
so that, you have radius, not diameter
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OpenStudy (anonymous):
So would the radius be 40.8?
OpenStudy (anonymous):
@Loser66
OpenStudy (anonymous):
I dont understand what your saying?
OpenStudy (loser66):
close the post first
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
i Have the midpoint its -3,2
OpenStudy (loser66):
yup
OpenStudy (loser66):
so, you get a) now b
OpenStudy (loser66):
distance between the point (-10,-2) and midpoint(-3,2)
d= \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\) what do you get?
OpenStudy (anonymous):
40.8
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OpenStudy (anonymous):
noo wait
OpenStudy (loser66):
nope, it is \(\sqrt{65}\) right?
OpenStudy (anonymous):
I got sqrt 1601 lol
OpenStudy (loser66):
and that distance is radius of the circle
OpenStudy (anonymous):
ohhh I was ADDING And not SUBTRACTING *facepalm*
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