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Mathematics 26 Online
OpenStudy (anonymous):

?? So confused. I suck at circles. Help Please

OpenStudy (anonymous):

OpenStudy (anonymous):

@Loser66 @mathstudent55

OpenStudy (loser66):

a) apply formula of midpoint b) apply distance formula of one of the point and the midpoint c) after having the radius and the midpoint, apply all in the equation of the circle About what are the formulas: Google

OpenStudy (anonymous):

Thank You!!!!!!

OpenStudy (anonymous):

For B, once I have the answer of the distance formula do I att the answer to the midpoint or? @Loser66

OpenStudy (anonymous):

Or do I divide the answer by two because the distance formula would make the diameter?

OpenStudy (loser66):

show me your work, I can check and correct the mistake (if there is some)

OpenStudy (loser66):

Re-read my instruction, I said: b) apply distance formula of one of the point and the \(\color{red}{midpoint}\)

OpenStudy (loser66):

not 2 given points

OpenStudy (loser66):

so that, you have radius, not diameter

OpenStudy (anonymous):

So would the radius be 40.8?

OpenStudy (anonymous):

@Loser66

OpenStudy (anonymous):

I dont understand what your saying?

OpenStudy (loser66):

close the post first

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i Have the midpoint its -3,2

OpenStudy (loser66):

yup

OpenStudy (loser66):

so, you get a) now b

OpenStudy (loser66):

distance between the point (-10,-2) and midpoint(-3,2) d= \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\) what do you get?

OpenStudy (anonymous):

40.8

OpenStudy (anonymous):

noo wait

OpenStudy (loser66):

nope, it is \(\sqrt{65}\) right?

OpenStudy (anonymous):

I got sqrt 1601 lol

OpenStudy (loser66):

and that distance is radius of the circle

OpenStudy (anonymous):

ohhh I was ADDING And not SUBTRACTING *facepalm*

OpenStudy (loser66):

|dw:1400803145331:dw|

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