Question

DIRECTIONS: solve each system by substitution.
Problem:
y=6x+16
3x-3y=-3
please help me.

Answer 1

i need help

Answer 2

help

Answer 3

Since you know y in the first equation, substitute that into the "y" of the second equation:

\(3x-3(6x+16)=-3\)
Do you see that?

Answer 4

yes

Answer 5

So now you have just an equation with just on variable x, so you can solve for x:
\(3x-18x-48=-3\) (I distributed the -3 to each term in the parentheses)

Answer 6

ok i see that

Answer 7

\(-15x-48=-3\)
\(-15x=-3+48\)
\(-15x=45\)\[ x=\frac{45}{-15}=-3\]

Answer 8

let me write that down

Answer 9

ok i got that written down

Answer 10

Now you know the value of x... so you can plug in x = -3 into the first equation, and that will give you the value of y

Answer 11

ok

Answer 12

how exatly to i do that?

Answer 13

\(y=6x+16\)
You know \(x=-3\), so just put it in where \(x\) is:

\(y=6(-3)+16\)

Answer 14

ok

Answer 15

then what do i do?

Answer 16

just calculate \(6(-3)+16\)

remeber that the notation \(6(-3)\) means \(6 \text{ times} -3\)

Answer 17

ok thanks for taking your time to help me and have a great rest of the day

Answer 18

yw same to you!

Answer 19

ps you just gained a new fan

Answer 20

:) awesome

Answer 21

bye