Question

given the general identity tanx=sinx/cosx,which equation relating the acute angles, 11 years ago

Answer 1

@AltCode

Answer 2

can you help @Levity1

Answer 3

@e.mccormick

Answer 4

@phi please help?

Answer 5

@Pawtpie @ParthKohli

Answer 6

@Hero

Answer 7

It's asking "Which equation" shows a relationship between angles A and C based on the identity which implies that you have a list of answers (you have not yet posted) to choose from.

Answer 8

A. tanA=sinA/sinC
B. cosA=tan(90-A)/sin(90-c)
C.sinC=cosA/tanC
D.cosA=tanC
E. sinC=cos(90-c)/tanA

Answer 9

@Hero

Answer 10

i am thinking it is A

Answer 11

Can you explain using mathematical reasoning how you arrived at A as the answer?

Answer 12

in all honesty it is a guess

Answer 13

if its a right angle then it would be something like this

Answer 14

\[\tan=\frac{ opposite }{ adjacent }\]
\[Cos=\frac{ opposite }{ hypotenuse }\]

Answer 15

right?
\[\sin=\frac{ opposite }{ hypotenuse }\]

Answer 16

That isn't precisely what explain it. But you have it correct. There's a general rule which says that if angles A and C are complementary (meaning if they add to 90 degrees) then

sin(A) = cos(C)

For example suppose

A = 30°
C = 60°

Then

sin(30°) = cos(60°)

And
sin(60°) = cos(30°)

Therefore:
\(\tan(30°) = \dfrac{\sin(30°)}{\sin(60°)} = \dfrac{\sin(30°)}{\cos(30°)}\)

I hope that makes sense

Answer 17

somewhat. but i still dont understand how to get the answer i need. The tan i have is \[tanA=\frac{ sinA }{ sinC}\]

Answer 18

I just explained it. Read it ten more times.