Factor this 8y^2 + 6y + 1 Help please, math will be the death of me
There is an approach that I can show you on this if you would like?
Please, I am borderline moron when it comes to math dont know how im passing my senior year of math right now
One method that works if you have a factorable quadratic is this: First, identify a, b, and c for your quadratic. What is a? What is b? And, what is c?
If you do not recall, we can go over that quickly. :)
I dont know if this is quadratic, but the answer is something like this i just dont know the other number (2y ) (4y ) i dont know what goes in the middle of those parentheses
Well, actually you are off to a very good start. But what you want to look at next is the final term of your quadratic, 1.
What would you multiply together to get 1?
like in general? the only thing that multiplys to 1 is 1
Exactly. So you have this: (2y 1)(4y 1)
And you also need to look at the signs on the terms in your quadratic
So, since the terms of your original quadratic are separated by + and another +
ah! see im so dumb
No, actually, it just takes practice and getting used to the patterns :)
So your original quadratic was 8y^2 + 6y + 1
and since you have + signs throughout, what must the signs be between 2y and 1 and between 4y and 1?
+
Yep
So then your factored quadratic is (2y + 1)(4y + 1)
Thank you for all your help! ;]
But you can always multiply them back together and combine like terms
to make sure it works.
You're welcome :D
By the way, if you want a few more tips on factoring quadratics, or if you have others you want to work on, I have a few more minutes.
Or if not, that's fine. :) Have a good night!
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