Question

Will medal!!

Cylinder A has a radius of 12 inches and a height of 6 inches. Cylinder B has a volume of 648π. What is the percent change in volume between cylinders A and B?

Answer 1

a. Cylinder B is 50% smaller than cylinder A.
b. Cylinder B is 75% smaller than cylinder A.
c. Cylinder B is 150% bigger than cylinder A.
d. Cylinder B is 200% bigger than cylinder A.

Answer 2

Cylinder B is smaller, so I'm thinking it's either a or b?

Answer 3

The answer is B, because half of A is no where near B

Answer 4

But are you sure B is the right answer? It doesn't seem right to me...

Answer 5

well find the volume of the cylinder...

Answer 6

I'm positive, A is 800pi and B is 600 but B is not 50% of A for sure, which narrows it down to 75%

Answer 7

100.48 is the volume of cylinder A... so what would I do from there?

Answer 8

volume of a cylinder\[\pi*r ^{2}*h\]

Answer 9

12^2 * 6

Answer 10

clearly not 100

Answer 11

then ignore the pi and just put it next to it

Answer 12

My mistake... 864pi sorry

Answer 13

now find the percentage change of volume

Answer 14

what is the formula for that?

Answer 15

Step 1: Divide the New Value by the Old Value (you will get a decimal number)
Step 2: Convert that to a percentage (by multiplying by 100 and adding a "%" sign)
Step 3: Subtract 100% from that

Answer 16

%change in volume=
\[\frac{ VA-VB }{ VA }*100\]

Answer 17

You really don't need to find the percentage of change because it becomes quite obvious that it't not 50%

Answer 18

648/864 = .75
.75 x 100 = 75%
So the answer is b then? @sidsiddhartha

Answer 19

Yes B is the answer

Answer 20

v=864-648/864=25%
so Cylinder B is(100-25)%= 75% smaller than cylinder A

Answer 21

thanks guys

Answer 22

^_^