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Simplify the attachment 7 -3/4 7 1/4 7 3/4 7
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\[\sqrt[4]{7}=(7)^{1/4}\]
\[\sqrt{7}=7^{1/2}\]
it's the second one i got it.
then use the rule \[\frac{ A ^{x} }{ A ^{y} }=A ^{x-y}\]
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5 -1/6 5 3/2 5 5/2 5 -5/6
\[\sqrt[3]{5}=5^{1/3}\]
\[\sqrt{5}=5^{1/2}\]
then the product rule \[A ^{x}*A^{y}=A ^{x+y}\]
use these rules for the numerator
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is the answer the 2nd or 3rd one?
i ave a really hard time with this math.
\[5^{-3/2}\]
5 -3/2?
yeah
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i don't have that as a choice but there is 5 3/2
check again your choices
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