Question

Simplify. square root of 5 over cube root of 5

5 to the power of negative 1 over 6



5 to the power of negative 1 over 6

5 to the power of 5 over 6
im not sure how to do this I thought u were supposed to subtract the exponents but like idk

Answer 1

\[\huge \frac{ \sqrt{5} }{ \sqrt[3]{5} }?\]

Answer 2

yes sorry

Answer 3

\[\sqrt{5} \implies 5^{1/2}\]
\[\sqrt[3]{5} \implies 5^{\frac{ 1 }{ 3 }}\]

Answer 4

Yes you're in the right path.

Answer 5

ok i thought that was how to do it but im not sure how they got the denominator to be 6

Answer 6

\[\huge \frac{ \sqrt{5} }{ \sqrt[3]{5} } \implies \frac{ 5^{\frac{ 1 }{ 2 }} }{ 5^{\frac{ 1 }{ 3 }} } \implies 5^{\frac{ 1 }{ 2 }-\frac{ 1 }{ 3 }}\]

Answer 7

Does that make sense?

Answer 8

\[\frac{ 1 }{ 2 }-\frac{ 1 }{ 3 } = ?\]

Answer 9

yes um -1

Answer 10

I see the problem, you need to work on your fractions, 1/2 -1/3 is not -1, it's actually 1/6.

Answer 11

o lol i suck at math but then it would 5 1/6 right

Answer 12

Correct or \[\sqrt[6]{5}\]