10 medals!! please help?
lol
you would need 10 accounts to give 10 medals
Nonetheless, I'd be willing to help if I'm able.
What is the question?
this is what i do -- I go to your profile and give you medals for previous questions you have answered....
ill give you if you really want? :))
@ankit @noseboy @niko can someone help?
@noseboy908
Hi abbie, you can use the fact that Volume of a solid is proportional to cube of the side! and Surface Area of the solid is proportional to square of the side!
So, Since we are given volume of both the solids, lets first find the ratio of sides, \(\Large \dfrac{V_1}{V_2}= \dfrac{s_1^3}{s_2^3}\) \(\Large \dfrac{1331}{216}= \dfrac{s_1}{s_2}\) take cube root on both sides, and you will get the ratio of sides!
that is supposed to be \(\Large \dfrac{1331}{216}= \dfrac{s_1^3}{s_2^3}\)
know whats the cube root of 1331 and 216 ?
I dont get it... so what do I have to do?
take the cube root on both sides of \(\Large \dfrac{1331}{216}= \dfrac{s_1^3}{s_2^3}\)
\(\Large \dfrac{\sqrt[3]{1331}}{\sqrt[3]{216}}= \dfrac{s_1}{s_2}\) so you will have to find out the cube root of 1331 and 216
11/6
correct! :)
so, the ratio of sides is s1/s2 = 11/6 now since the surface area is proportional to square of sides, we have \(\Large \dfrac{SA_1}{SA_2} = (\dfrac{s_1}{s_2})^2 \) \(\Large \dfrac{484}{SA_2} = (\dfrac{11}{6})^2 \) just find SA2 from this !
what next?
use 11^2 = 121 6^2 = 36
then cross-multiply!
I got 144
and you're absolutely correct! :)
Thankyou so much ^_^
welcome so much ^_^
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