write an equation of the circle with the given center and radius center: (-7,-6) and radius 2
Equation of circle with center (h,k) and radius 'r' is \(\Large (x-h)^2+(y-k)^2 = r^2\)
here, h,k = -7,-6 r=2 just plug in!
Okay so it'll be like this: (x-(-7)^+(y-(6)^=2^
Is this right?
yes whats \(\Large x-(-7) = ...?\)
'x' minus -7.
two negatives become a positive!
with the two negatives means the '7 turns into positive 7 right?
yess \(x-(-7) = x+7\) \(y- (-6) = ...?\)
y+6 right? So it would be (x+7)^ + (y+6)^=2 right?
you forgot to square the radius ? \((x+7)^2 + (y+6)^2 = 2^2 \\(x+7)^2 + (y+6)^2 = 4 \)
Okay so now I don't know what to do! What should I do next>
thats the equation of your circle! thats it!
OOOOOOOOOH! Okay then! Thanks so much for the help again! You're a real life saver! I totally appreciate it!
you're most welcome ^_^
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