Question

The weights of 1250 pumpkins are normally distributed with mean of 28 pounds and a standard deviation of 6 pounds. About how many of the pumpkins weigh more than 34 pounds. Equation will help.
1050
1000
250
200

Answer 1

This can be solved by using a standard normal distribution table. The z-score for 34 pounds is 1, the reason being that 34 is one standard deviation above the mean of 28 pounds.
Can use the table to find the cumulative probability for z = 1.00 and post the result? If you do this we can do the next simple steps.

Answer 2

You can use the table here if you need it:
http://lilt.ilstu.edu/dasacke/eco148/ztable.htm

Answer 3

@Cierra104 Are you there?

Answer 4

yes -2.0

Answer 5

do you subtract than divide or subtract then multiply

Answer 6

Did you use a standard normal distribution table? Your result is not a probability.

Answer 7

yes

Answer 8

This how i think i need to do it : 1250/28
Find deviation of 6 to 34?

Answer 9

I don't understand without an equation thats all i need along with equation for finder's deviation. I can figure the rest out.

Answer 10

Let p be the cumulative probability for z = 1.00. Then the approximate number of pumpkins weighing more than 34 pounds is given by:
\[(1-p) \times1250=you\ can\ calculate\ (when\ you\ find\ the\ value\ of\ p)\]

Answer 11

The z-score is found as follows:
\[z=\frac{X-\mu}{\sigma}=\frac{34-28}{6}=1.00\]

Answer 12

1-2 x 1250=-1250 of 34?
or 28

Answer 13

i got c

Answer 14

Where did you get the value of -2 from?

Answer 15

table

Answer 16

The value of p must be found from the table here, using z = 1.00
http://lilt.ilstu.edu/dasacke/eco148/ztable.htm

Answer 17

.8341

Answer 18

Good work! You are correct. The approximate number of pumpkins weighing more than 34 pounds is given by:
\[(1.0000-0.8413) \times1250=you\ can\ calculate\]

Answer 19

i got 198.375 though
do i need to divide?

Answer 20

You are correct. Just round up to 200 and find the correct answer choice is D.

Answer 21

or round up.
do i always use that chart when it comes to deviation equation or does it depend.
my teacher doesn't provide me with this at all.

Answer 22

There are other methods to solve this question. The empirical rule for a normal distribution could be used, for example.

Answer 23

okay thanks
add me as friend will you be my tutor please i have sats coming up soon

Answer 24

You're welcome :) I am happy to try to help you in future if you post more questions.

Answer 25

ok great.

Answer 26

you good @ chem?