Question

Anyone else can answer this?

Answer 1

I know the answer is C but I thought it was supposed to be B

Answer 2

Anyone Can explain the working?

Answer 3

@Kainui

Answer 4

Sure, so what I would do first is determine the limiting reagent, so by comparing we need 1 mol of that carbon compound to every 3 mols of oxygen gas. So if we look, it says 10 cm^3 and 60 cm^3 so we can see that the limiting reagent is going to be the carbon compound since it will use up 30 cm^3 of the oxygen gas and still have leftover oxygen to react later.

Ok so now we just see that for every 1 cm^3 of the carbon compound we get 1 cm^3 CO2, 1 cm^3 SO2, and 2 cm^3 H2O right? But we're reacting 10cm^3 of the stuff so we will just multiply each of these values by 10 cm^3 as well to get our total product which is:

10 cm^3 CO2, 10 cm^3 SO2, and 20 cm^3 H2O. So now what? Well it says afterwards it's cooled to room temperature. Take a drink of water to realize that H2O is liquid at room temperature, so as far as gas is concerned we will just have the 10 cm^3 of CO2 and 10cm^3 of SO2. Now, don't forget we only reacted 30 cm^3 of the 60 cm^3 of O2 gas and we still have 30 cm^3 left over! Add all those gasses up to get: 10+10+30=50 cm^3.

;)

If you want me to clarify anything just ask, I hope that was straightforward enough!

Answer 5

@Kainui OMG I'm sooooo sorry you had to write so much!!
Thank you, Thank you Thank you Thank youuuuuuuu!! <3333

Answer 6

Haha no problem I'm glad I could help! If you have more questions don't hesitate to ask, I'm here to help you out. I'm a real fast typer so it really doesn't take that long to type that out lol.

Answer 7

@Kainui :D

Answer 8

Somy likes to thank you too

Answer 9

lmao yeah thanks a lot!!! @Kainui