Question

000

Answer 1

@sarah786 @ParthKohli can someone please help me?? this makes no sense?

Answer 2

First, try to find out the electronic configuration of Indium. A 3+ indicates that there are three electrons removed from the outermost shell.

Answer 3

ok, I did that earlier. Is it 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d8?

Answer 4

You need to remove the electrons from the outermost shell, i.e., the one with the principle quantum number 5.

Answer 5

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p1

The outermost shell is 5s2 5p1.

So there are 3 electrons in the outermost shell. But since you remove three electrons from the outermost shell to get In3+, you now have the following electronic configuration of In3+

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d10

5 is no longer the outermost shell because we removed all the three electrons from it. The outermost shell is now the one with the principal quantum number = 4.

Answer 6

So the outermost shell configuration is 4s2 4p6 4d10.

Answer 7

Oh wow, that makes sense :)

Answer 8

so you wouldn't call 4p or something a shell...is that a subshell?

Answer 9

Yes, 4p is a subshell and so is 4s and 4d. But 4s2 4p6 4d10 is the configuration of the whole shell.

Answer 10

oh, ok :) great! Thank you SOOO much!

Answer 11

So how many electrons are there in the outermost shell?

Answer 12

18

Answer 13

Good!