Question

Trig unit help?
@iPwnBunnies

Answer 1

Tru, amplitude is -4.
For the period, when the variable is in the argument, you want it equal to 2pi. Since 2pi is a complete circle.
2x = 2pi. Solve for x, that's the period.

Answer 2

The phase shift, I can't remember. >.<

Answer 3

phase shift:

sin(x+ph)

Answer 4

in this case:\[sin(mx+ph)\to sin(m(x+ph/m))\]

Answer 5

opposite signs move in opposite directions as with any horizontal shift of a graph

Answer 6

and amplitude is never negative if memory serves.

Answer 7

memory could be frazzled tho lol

Answer 8

I got pi/2 ? is that right?

Answer 9

Oh, tru. Amplitude can't be negative. I thought all the choices had -4 as amplitude, got a bit confused.

Answer 10

its a pi/2 shift yes, but take care of the direction ...

Answer 11

the period is multiplied so its quicker than the normal 2pi

Answer 12

2x = 2pi when x=pi ... the period is pi

Answer 13

hmm, so:
amplitude = 4
period = pi
phase shift = - pi/2
is that correct?

Answer 14

lets review this:

-A sin(\(\rho\)x+\(\phi\))

A sin(-\(\rho\)x-\(\phi\))
A sin(\(\rho\)(-x-\(~\phi\)/\(\rho\))

Answer 15

yeah, in going with that one, 4, pi, -pi/2

Answer 16

ok, thanks :)

Answer 17

your welcome .. we can dbl chk with the wolf

Answer 18

ok :)
do you have time to help with the other one?

Answer 19

the wolf is confused lol

apparently -4sin(2x+pi) = 4sin(2x) making the phase shift irrelevant.

Answer 20

1 more

Answer 21

ok :D that's all I have left, anyway XD

Answer 22

you have a high and low tide, this gives you your amplitude and midline what are they?

Answer 23

high tide is 9 feet, low tide is 1 foot....

Answer 24

is the amplitude 4, the period 12, the vertical displacement is 5 .... and i don't know what the midline is.... ? is it right?

Answer 25

midline is the vertical displacement ... its the line the runs the the middle of the wave

Answer 26

OH! >.< ok

Answer 27

so, what I know is the equation is h(t) = a*cos((2pi/P)*t) + b ....

Answer 28

when b is 0 we are oscillating about y=0 :)

Answer 29

kx = 12 when x=2pi

2pik = 12 when k=6/pi for the multipier but i dont see that as an option

Answer 30

hmmm......
I got:
h(t) = 4*cos((pi/6)*t) + 5
but that was yesterday... and I don't remember what I did O.o

Answer 31

its pi/6 :)

Answer 32

2pi = 12k for some reason doesnt register all the time

Answer 33

ok...

Answer 34

thanks to all! :)

Answer 35

YAY!!! THX SO MUCH!! 100% on my assignment ^_^
(does little happy dance)