In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion of sucrose, given that both gases are at STP?
C12H22O11 + 12O2 - 12CO2 + 11H2O
A) 125 liters
B) 500 liters
C) 250 liters
D) 268.8 liters

Question

In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion of sucrose, given that both gases are at STP?
C12H22O11 + 12O2 -> 12CO2 + 11H2O
A) 125 liters
B) 500 liters
C) 250 liters
D) 268.8 liters

aaronq · Answer

It's the same concept as the previous question you posted, since the volume of a(n) (ideal) gas is proportional to the moles, you can set up a ratio of the volume of the gases and their coefficients.

 $\sf \dfrac{V~of~O_2}{O_2's~coefficient}=\dfrac{V~of~CO_2}{CO_2's~ coefficient}$

anonymous · Answer

whats the answer