Question

In the following reaction, how many liters of oxygen will react with 124.5 liters of propane (C3H8), at STP?
C3H8 + 5O2 d 3CO2 + 4H2O
A) 24.9 liters
B) 622.5 liters
C) 373.5 liters
D) 41.5 liters

Answer 1

this is related to the problems you posted earlier, make a ratio of the volume and the coefficients of what you're interested in.

\(\dfrac{V~of ~C_3H_8}{C_3H_8's ~coefficient}=\dfrac{V~of~O_2}{O_2's~ coefficient}\)

Answer 2

Answer is B - Let me know if you want me to write it out.

Answer 3

Since all are gases one may use a shortcut that tells us we can use liters directly as moles. All you need to do is to convert 124.5 L propane to oxygen using the coefficients in the balanced equation.
124.5L x (5 moles propane/1 mol oxygen) = 622.5 L O2.

My handwriting is bad, I did this for you.