Question

Use the graph below to answer the question that follows:

Answer 1

It is fx 2 cos x-pi/2

Answer 2

when u are evaluating the graph, u take some points on it for cross verification
eg: when x=0 on the graph,y=2
similarly x=pi/2, y=0
substitute them in the options, u will get answer

Answer 3

I am not sure?

Answer 4

U know where the amplitude is and period is , it is cos because it is not starting from 0 and positive 2 because if its -2 then the graph would be flipped

Answer 5

take a point (0,2)
substitute x=0 in options answer should be y=2
cospi/2=cos(-pi/2)=0
sinpi/2=1
sin(-pi/2)=-1
find where y becomes 2 when x=0

Answer 6

but given (x-pi/2) in the equation, so it should be other way around

Answer 7

So is it \[f(x)=2\cos(x-\pi/2)\]

Answer 8

no answer should be sine

Answer 9

it is B

Answer 10

\[f(x)=-2\sin(x-\pi/2)\]

Answer 11

yaa right

Answer 12

Standard form of cosine function: y=Acos(Bx-C), with A=amplitude, Period=2π/B, phase-shift=C/B
use it in your question

Answer 13

So it is what?

Answer 14

@Loser66

Answer 15

here A=-4
B=3
C=pi
so substitute them in the above formula

Answer 16

This

Answer 17

what si question here
i cant see it

Answer 18

No that is for the equation you gave me

Answer 19

@Loser66

Answer 20

The answer is D, thanks @Loser66

Answer 21

why thanks me?? I did nothing for you,

Answer 22

What cosine function represents an amplitude of 3, a period of π, no horizontal shift, and a vertical shift of 2? (5 points)

f(x) = 2 cos 2x + 3

f(x) = 3 cos πx + 2

f(x) = 2 cos πx + 3

f(x) = 3 cos 2x + 2

Answer 23

it is C i think not D @gamer456148

Answer 24

@Loser66 Is it C?

Answer 25

which question???

Answer 26

to me, it's D

Answer 27

amplitude is negative in the question, isnot it???

Answer 28

sorry i think we should take mod for anser
pardon me

Answer 29

@Loser66

Answer 30

@minoz for the previous question, I chose D because of the vertical phase shift D=1, If you choose C, (because of the amplitude -3, right? if it is so, I don't know how to say. Because I was taught that amplitude = 1/2 (max +min), therefore, no matter what the sign of A is, the amplitude is ALWAYS positive), then how do you explain for D =+1 while in C option, D =-1???
@gamer456148 I guess!!! you are not sure about what you learn for this kind of problem. You ask many questions (or your homework) about this. All of them are same topic. Can you try one? if you were wrong, we can help you correct. If I help you do your homework, who get the stuff? you or me?? think of it.
the answer for the last question is D

Answer 31

#5 is D and #6 is D

Answer 32

those are my choices.

Answer 33

This one is D

Answer 34

And this one

Answer 35

yup

Answer 36

I think it is \[-8/\pi\]

Answer 37

@minoz

Answer 38

(f(2pi)-f(pi))/(2pi-pi)=(-4-4)/pi=-8/pi
u r right