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Mathematics 21 Online
OpenStudy (anonymous):

this one?

OpenStudy (anonymous):

OpenStudy (anonymous):

@hartnn

hartnn (hartnn):

1.04 = 1+0.04 = 100% +4% so,its increase in value per year!

OpenStudy (anonymous):

thank you! what about this one?

OpenStudy (anonymous):

93% in Decimal form is 0.93... and since it is positive I would Assume C.

hartnn (hartnn):

since 0.93 is less than 1, its a decay

OpenStudy (anonymous):

Oh :(

OpenStudy (anonymous):

so it would be D?

hartnn (hartnn):

you can confirm by plugging in x=1,2,3,4...you'll see that value decreass...

OpenStudy (anonymous):

Yes... it's D, Trust Hartnn :P

OpenStudy (anonymous):

did i get this one right? @hartnn

hartnn (hartnn):

yes, correct :)

OpenStudy (anonymous):

how about this one?

hartnn (hartnn):

correct!

OpenStudy (anonymous):

im taking this practice reveiw for my algebra 1 exam. can i take a screen shot of the problems (alot of them youve already helped me with) and attach them ? can you tell me whihc ones i got wrong? it would really help a lot!

hartnn (hartnn):

if i have enough time, then sure, i will help :)

OpenStudy (anonymous):

thank you so much!

hartnn (hartnn):

correct

OpenStudy (anonymous):

hartnn (hartnn):

1.005644^4 = 1.02276784858

OpenStudy (anonymous):

so its would be C?

hartnn (hartnn):

\(\huge a^{bc} = (a^b)^c\) yep C

OpenStudy (anonymous):

okay

hartnn (hartnn):

yah, correct

OpenStudy (anonymous):

I was still counting lol

OpenStudy (anonymous):

hartnn (hartnn):

shift down by 3 so subtract 3 0.5^x-3 comparing with 0.5^x-k we get k=3

OpenStudy (anonymous):

okay thank you

hartnn (hartnn):

correct!

OpenStudy (anonymous):

hartnn (hartnn):

thats also correct :)

OpenStudy (anonymous):

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

Wait is 8 x or y

hartnn (hartnn):

x =- 6, y= 8

hartnn (hartnn):

so you're correct!

OpenStudy (anonymous):

okay (=

OpenStudy (anonymous):

I think your right.

hartnn (hartnn):

yes, correct :)

OpenStudy (anonymous):

hartnn (hartnn):

thats correct too :)

OpenStudy (anonymous):

hartnn (hartnn):

correct

OpenStudy (anonymous):

hartnn (hartnn):

correct!

OpenStudy (anonymous):

Yay! thank you so much! i have another reveiw to do tomorrow. will you be on tomrrow night if i need some help????

hartnn (hartnn):

if i am online, i will help :) couldn't say anything for sure .... :)

OpenStudy (anonymous):

i have one more question if thats okay?

hartnn (hartnn):

sure

OpenStudy (anonymous):

Task 3 Part 1: Create a scenario for an arithmetic sequence. For example, Jasmine practices the piano for ______ minutes on Monday. Every day she ___________ her practice time by _________. If she continues this pattern, how many minutes will she practice on the 7th day? Be sure to fill in the blanks with the words that will create an arithmetic sequence. Use your scenario to write the function for the 7th term in your sequence using sequence notation. Part 2: Create a scenario for a geometric sequence. For example, Anthony goes to the gym for ______ minutes on Monday. Every day he _________his gym time by ____________. If he continues this pattern, how many minutes will he spend at the gym on the 5th day? Be sure to fill in the blanks with the words that will create a geometric sequence. Use your scenario to write the formula for the 5th term in your sequence using sequence notation. Part 3: Use your scenario from part 2 to write a question that will lead to using the geometric series formula. Use the formula to solve for Sn in your scenario.

OpenStudy (anonymous):

i just need part 3! here is what i have for part two and some of part 3.... part 2: Anthony goes to the gym for 50 minutes on monday. Every day he doubles his gym time. function- An=50(2)^n-1 on the 5th day- A5=50(2)^4 A5=800 part 3: If anthony goes to the gym for 50 minutes on monday. Each day he doubles his gym time by a ratio of two.

hartnn (hartnn):

so we need to make a question, so that we can use the formula \(A_n = A_1 r^{n-1} \)

OpenStudy (anonymous):

so how do we do that?

hartnn (hartnn):

we already used it in 2nd scenario...but ok, to use it again, we can make a question, that after how many days, Antony will go to gym for 3200 minutes!

hartnn (hartnn):

here, A_n = 3200 A1 = 50 r= 2 find n

OpenStudy (anonymous):

so for the question i should write, anthony goes to the gy for 50 minutes on monday. each day he doubles his gym time. How many days will it take anthony to work out in the gym for 3200 minutes?

hartnn (hartnn):

thats correct.

OpenStudy (anonymous):

okay so the equation would look like..?? im confused on that part because it is saying to solve for sn??

hartnn (hartnn):

you know exactly which formula the asker means by "geometric series formula"

hartnn (hartnn):

because Sn means sum of n terms so that formula which the asker is talking about, might be the sum formula

hartnn (hartnn):

which is \(\Large S_n =A_1 \dfrac{r^n-1}{r-1}\)

hartnn (hartnn):

if you need th question for sum formula, then the right question would be "In 5 days (or 6 or 7 or whatever), how many total number of minutes, will have Antony gymmed?"

hartnn (hartnn):

then you would use that Sn formula with A1 = 50 r =2 n=5

OpenStudy (anonymous):

so instead of asking how many days it will take for him to have 3200 minutes in the gym i need to ask in five days how many minutes will he have? didnt i do that in art 2?

hartnn (hartnn):

in art 2, it was how many minutes on 5th day only... here we are finding sum or total minutes its like asking, in all, from 1st day to last(5th) day, how many total number of minutes were spent gymming

hartnn (hartnn):

50 + 100 + 200 + 400 + 800

hartnn (hartnn):

if you use the sum formula you will get the same answer as you'll get for above

hartnn (hartnn):

which is 1550 minutes

OpenStudy (anonymous):

okay so the sum formula with the numbers all plugged in would look like sn=(50^2n-1)/2

hartnn (hartnn):

no... \(\Large S_n = 50 \dfrac{2^5-1}{2-1}\)

hartnn (hartnn):

n=5 denominator = r-1 = 2-1 = 1

OpenStudy (anonymous):

oh okay hold on let me solve it

OpenStudy (anonymous):

1550?

OpenStudy (anonymous):

thank you so much! you really helped!

hartnn (hartnn):

welcome ^_^ happy to help :)

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