If cos Θ = -5/2 and tan Θ > 0, what is the value of sin Θ? Explain bby
@iPwnBunnies
I ovb. know basic trig, but I don't understand wtf these types of questions are talking about
\(\tan\theta = \frac{\sin\theta}{cos\theta}\) So if \(\tan\theta > 0\) then \(\sin\theta < 0\) because \(\cos\theta\) is negative.
I mean, I know how to solve it by the steps and rules given. sin Θ = (-√21)/5 But I like to see math visually... I don't get it.
Obviously, we're dealing with a right triangle. Also, you can think of the right triangle as being in the 3rd Quadrant of a coordinate plane. In Q3, tangent is positive, cos and sin are negative.
Ok hold on. I'll draw.
I get it bunnies don't draw it xD
Sweet. Yeah, so find the reminaing leg of the pseudo triangle, and find the sine.
You might wanna remember this. |dw:1401045658652:dw| All Students Take Calculus. All trig functions positive in Q1, sin positive in Q2, tan in Q3, cos in Q4. And their reciprocal counterparts.
But I just don't "see" it you know? I see mathematics (particularly mathamatical models) as common sense. In this situation, I just know the rules, not how to solve it individually. Why DF is the tangent positive while the Cosine and sine are negative in Q3.
I think of it like polar coordinates and regular coordinates.
BUNNIES I DON'T WANT TO REMEMBER IT xD I want to know the logic of it lol
The hypotenuse is like a polar line, extending to some (x,y) coordinate.
@Applesdaaasdasfdsfda if you look at my equation that I first stated, you'll see the mathematics behind why both cosine and sine are negative.
And you know that like, tan(x) = y/x, cos(x) = x/hyp So, since y and x are both negative in Q3, tan would be positive. Everything else would be positive.
I should say the "mechanical" mathematics...
Yeah, dummyguy's thing works too. Two different ways to look at it.
Ohhhh I gettttchu. Thx bby ♥ P.S. Dummyguy, you too
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