Question

prove: sin Ɵ-sin Ɵ-cos^2 Ɵ=sin^3Ɵ someone help please I am so stuck

Answer 1

The way you wrote the question.... I am not going to assume or redetermine anything.

\(\Large\color{black}{ \bf sin Ɵ-sin Ɵ-cos^2 Ɵ=sin^3Ɵ }\)
\(\Large\color{black}{ \bf -cos^2 Ɵ=sin^3Ɵ }\)
\(\Large\color{black}{ \bf -(1-sin^2 Ɵ)=sin^3Ɵ }\)
\(\Large\color{black}{ \bf -1+sin^2 Ɵ=sin^3Ɵ }\)
\(\Large\color{black}{ \bf sin^3Ɵ +1-sin^2 Ɵ=0 }\)
\(\Large\color{black}{ \bf sin^3Ɵ -sin^2 Ɵ+1=0 }\)

say, let sinƟ=a and solve.
Let me know if you need more help.

Answer 2

I dont understand this at all would that be the answer?0.o

Answer 3

\(\Large\color{black}{ \bf a^3 -a^2 +1=0 }\)

Answer 4

you cant subtract the a^3-a^2 right? so do i just move the 1 over?

Answer 5

use Newton's Method