What volume of concentrated hydrochloric acid (12.0 M HCl) is required to make 2.0 liters of a 3.0 M HCl solution? A) 5.0 liters B) 0.24 liters C) 0.50 liters D) 6.0 liters
Have you used this equation before? \( M_1 V_1 = M_2 V_2 \)
No I haven't
Or perhaps instead of M's it was C's: \(C_1 V_1 = C_2 V_2 \). But, that is the equation we should use in this problem. There may be more information on it here: http://www.chemteam.info/Solutions/Dilution.html Basically, the product of the molarity and volume of the concentrated solution equals the product of molarity and volume of a diluted solution. We would substitute: Molarity1 = 12 M, Volume1 = unknown. Molarity2 = 3 M, and Volume2 = 2 L. \( 12 \times V_1 = 3 \times 2 \) And solve for V_1.
Thank you
You're welcome. :)
what was the answer? i know its not 0.25 liters
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