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Mathematics 20 Online
OpenStudy (anonymous):

Is this right?

OpenStudy (anonymous):

OpenStudy (solomonzelman):

no, it's left ;)

OpenStudy (anonymous):

Is it correct?:P

OpenStudy (p0sitr0n):

ln x can never have a negative x

OpenStudy (anonymous):

So it is a?

OpenStudy (p0sitr0n):

lnx for x>=1

OpenStudy (solomonzelman):

yes for ln, that is always the case, but not for log....

OpenStudy (anonymous):

So it is A? I have to make sure it's right so I pass haha.

OpenStudy (primeralph):

No.

OpenStudy (anonymous):

Wait what?

OpenStudy (primeralph):

ln(1) = 0.

OpenStudy (anonymous):

I'm getting really confused.....

OpenStudy (solomonzelman):

yeah me too. When I replied I mean that the log of a negative is a possible case, but ln of negative.

OpenStudy (arbershabani97):

http://mathematicsi.com/graph-of-yln-x-and-graph-of-yex/ here is a better explanation than I can give to this

OpenStudy (anonymous):

Okay so is A right or no? People are getting me all confused....

OpenStudy (arbershabani97):

D it's D

OpenStudy (primeralph):

I said no. Read.

OpenStudy (anonymous):

It's D?

OpenStudy (solomonzelman):

I can say no with many other comments in the thread, and it won't make sense what exactly I am going on

OpenStudy (anonymous):

I think it's B..

OpenStudy (arbershabani97):

in a graphing calculator is a D, just read the link a commented earlier and you'll understand it easier

OpenStudy (anonymous):

So it's D..

OpenStudy (arbershabani97):

yes

OpenStudy (solomonzelman):

\[y=\log_ex~~~~~~~~~e^y=x\]You can't get any negatives so eliminate a.

OpenStudy (anonymous):

Okay so it's D. That's what I'm going to enter..

OpenStudy (solomonzelman):

You just keep guessing, unfortunately -:(

OpenStudy (anonymous):

That's what everyone is saying.... I was just going with what the graphing calculator said......

OpenStudy (arbershabani97):

it is a hard thing to be explained, but if you understand y=e^x you'll understand this by going in that link

OpenStudy (solomonzelman):

where do you get y=e^x may I ask ?

OpenStudy (arbershabani97):

e^x is the inverse of ln^x, so if you find the e^x by replacing x with 0 , 1 ,2, you just find the inverse on the graph

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