Is this right?
no, it's left ;)
Is it correct?:P
ln x can never have a negative x
So it is a?
lnx for x>=1
yes for ln, that is always the case, but not for log....
So it is A? I have to make sure it's right so I pass haha.
No.
Wait what?
ln(1) = 0.
I'm getting really confused.....
yeah me too. When I replied I mean that the log of a negative is a possible case, but ln of negative.
http://mathematicsi.com/graph-of-yln-x-and-graph-of-yex/ here is a better explanation than I can give to this
Okay so is A right or no? People are getting me all confused....
D it's D
I said no. Read.
It's D?
I can say no with many other comments in the thread, and it won't make sense what exactly I am going on
I think it's B..
in a graphing calculator is a D, just read the link a commented earlier and you'll understand it easier
So it's D..
yes
\[y=\log_ex~~~~~~~~~e^y=x\]You can't get any negatives so eliminate a.
Okay so it's D. That's what I'm going to enter..
You just keep guessing, unfortunately -:(
That's what everyone is saying.... I was just going with what the graphing calculator said......
it is a hard thing to be explained, but if you understand y=e^x you'll understand this by going in that link
where do you get y=e^x may I ask ?
e^x is the inverse of ln^x, so if you find the e^x by replacing x with 0 , 1 ,2, you just find the inverse on the graph
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