Ask your own question, for FREE!
Physics 23 Online
OpenStudy (anonymous):

A car travels in a straight line at 90.0 m/s for 1000 m and then travels at 60.0 m/s for the next 1000 m. What is the average velocity?

OpenStudy (studybird123):

I want you to know Khanacademy.org is a good website and will explain everything here is a link https://www.khanacademy.org/science/physics/one-dimensional-motion/displacement-velocity-time/v/calculating-average-velocity-or-speed to your question

OpenStudy (studybird123):

@caneschik05 I hope it helps!

OpenStudy (studybird123):

Are you good? @caneschik05

OpenStudy (studybird123):

Hello?

OpenStudy (anonymous):

We know that the car travelled a total of 2000m. We just need to know the time it took to travel this distance. How long did it take to travel the first 1000m? When given a distance and a speed, we can find the time by: \[Time = \frac{Distance}{Speed}\]

OpenStudy (studybird123):

Whoever gave me the medal thanks!

OpenStudy (studybird123):

Thank you fo explaining the problem out cause I couldn't I had to do something

OpenStudy (anonymous):

I'm still not sure how to solve this because the problem he did was already given the time.

OpenStudy (anonymous):

Nevermind I figured it out, thank you!

OpenStudy (studybird123):

Ok!

OpenStudy (anonymous):

Average speed equals total distance upon total time. Total distance is 2000 m Total time is (1000/90)+(1000/60) that is (15/54) Therefor average speed equals 72 m/s

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!