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How do you solve this complex number equation?
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\[|z ^{2}-9i|=16|\frac{ 1 }{ i }-\frac{ 9 }{ z ^{2} }|\]
\(\LARGE\color{blue}{ \bf ±(z^2-9i)=16(\frac{1}{i}-\frac{9}{z^2}) }\)makes sense to re-write it like this, right?
but it's modulus
Wait, I thought it's absolute value.
No sadly xD
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dang:) I actually never learned that. surprisingly. I solved even higher level problems like calc 1,2,3 but I have some empty spaces in my knowledge -:(
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