Question

Part 1. Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model.

a(√x+b)+c=d

Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneous.

Part 3. Explain why the first equation has an extraneous solution and the second does not.

Answer 1

I can help you tomorrow. I have to go now. Sorry.

Answer 2

@SolomonZelman

Answer 3

Can you help?

Answer 4

I really need this for tommorow...

Answer 5

hello? @SolomonZelman

Answer 6

there is no reason to tag me. Sorry.

Answer 7

ok im sorry...

Answer 8

can we start with 1?

Answer 9

@SolomonZelman

Answer 10

for part one, what have you tried to do ?

Answer 11

ok... i wrote 1 equation:
2(√x+3)+4=5
That is a extraenous one but i cant think of one thats not

Answer 12

yeah, kind of hard to do that... anyway , for part 2, what do you get ?

Answer 13

I would write

2(√x+3)+1=9

Answer 14

for non extraneous?

Answer 15

this is for extraneous.

2(√x+3)+1=9

solution,

2(√x+3)=9-1
2(√x+3)=8
(√x+3)=4
x+3=16
x=13

Answer 16

ok thanks but what about the steps for the extraneous one?
2(√x+3)+4=5
2(√x+3)=1
√x+3=0.5
x+3=0.5
x=-3.5?

Answer 17

I AM thinking...

2(√x+1)+3=-5
2(√x+1)=-5-3
2(√x+1)=-8
(√x+1)=-4

Answer 18

and no x-value will make the root be equal to -4 :)

Answer 19

as extraneous?

Answer 20

the last one?

Answer 21

yup

Answer 22

Well if you have

2(√x+1)+3=-5

with the solution below

2(√x+1)=-5-3
2(√x+1)=-8
(√x+1)=-4

and knowing that such a value that makes the root =-4 doesn't exist what do you think ?

Answer 23

no hold on, sorry

Answer 24

it does work if x=15

Answer 25

b/c √16=±4

Answer 26

idk the non extraneous one.

Answer 27

hmm... what about well we already had one remember
non extraneous means a solution and that one had it :)

Answer 28

sorry, I can't help . I did whatever I can.