Find the limit of the function algebraically. limit as x approaches five of quantity x squared minus twenty five divided by quantity x minus five.
\[\lim_{x \rightarrow 5} \frac{ x^2-25 }{ x-5 }\]
Well if we put a 5 in that equation we get 0/0, so we should look for stuff that we can factor out. You might have noticed that the numerator is a difference of squares.
formula for difference of squares \[a^2-b^2=(a-b)(a+b)\] so can you apply that to the numerator?
Yes but they need to do it algebraically, so not using L'Hopital's rule
so how do i get the answer
We need to get rid of that x-5 in the denominator because when we plug in x=5 we get a 0 in the denominator... So do what I said above and use the difference of squares on the numerator.
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