Question

Show that

\[12C5= 12C7\]

Answer 1

Could that be a combination?

Answer 2

yah sorry, i couldnt write it correctly

Answer 3

\[nCr = \frac{ n! }{ r!(n-r)! }\]

Answer 4

yes, you may use the definition to prove.
but to *see* they're equal, think of below :
Number of ways of choosing 5 objects from 12 objects = Number of ways of leaving 7 objects behind

Answer 5

Knowing that relation may help

Answer 6

\[\frac{ 12! }{ 5!7! } = \frac{ 12! }{ 7!5! }\]

Answer 7

@ganeshie8 is that correct?

Answer 8

@Johnbc

Answer 9

Correct

Answer 10

You will now notice that you have the same equation on both sides so you have proven they are equal to each other