Question

fx=1+(1/x)-(1/x^2)
f'=0+(1/1)-(1/1^2) or 0? Please help..

Answer 1

The question is unclear. Are you supposed to find the derivative of
\[f(x)=1+\frac{1}{x}-\frac{1}{x^2}\]
and evaluate it for \(x=1\) or something?

Answer 2

Yes, in order to set x=0 for critical points.

Answer 3

Well the derivative would be
\[f'(x)=-\frac{1}{x^2}+\frac{2}{x^3}\]
If you want to find the critical points, set it to 0 and solve for \(x\):
\[\frac{2}{x^3}-\frac{1}{x^2}=0~~\iff~~x^3\left(\frac{2}{x^3}-\frac{1}{x^2}\right)=0\cdot x^3~~\iff~~2-x=0\]

Answer 4

Thank you, let me work on this. Thanks again.

Answer 5

yw