If sin A , cos A , tan A are in Geometric Progression . then cos^3A+cos^2A = ??
well what does a geometric progression tell us about how the terms are formed?
cos a=rsina tan a=r^2sina
correct, another way to look at it may be from the center out in this case: sin, sin cot, sin cot cot (= tan)
had some competing thoughts lol
cos tan = sin cos = cos cos sin/cos^2 = tan
sin/cos^2 needs to equal cot giving us cos^2 = sin tan
.... need paper lol
cos^3+cos^2 cos^2(cos + 1) (1-sin^2)(cos + 1) (1 + sin) (1 - sin) (cos + 1) just some reworkings to try to get it into some useable format
is there any more context to the question? any idea as to what its looking for as a solution? is it a proof, or something else?
do we need to solve for A?
answer is given as 1. thats about it. we need to find cos^2A+cos^3A if sin,cos, tan are in gp
yeah, solving for A is paramount then
sinA * r = cosA if r = cot(A) sinA*r^2 = tanA if r^2 = secA or a geometric mean might help too cosA = sqrt(sinA tanA) cos^2A = sin^2A/cosA cos^3A = sin^2A cos^3A = 1 - cos^2A got it
ohohoh. yeah. didnt see that. i was trying to break down cos^2 A simultaneously. xD Thankyouu. :)
youre welcome .... the geometric mean made this much simpler
Join our real-time social learning platform and learn together with your friends!