Question

HELP!!
fx=ln(1-lnx) need f' then solve for critical values..

Answer 1

\[-\frac{ 1 }{ 1-\ln(x) }\frac{ 1 }{ x }=\frac{ df(x) }{ dx }\]

Answer 2

Great, thanks..How would you solve this for critical values?

Answer 3

\[-\frac{ 1 }{ x-xln(x) }=\frac{ df(x) }{ dx }\]
Wheatever values of x make the function undefined (x-xln(x)=0) will be your critical values for x

Answer 4

so it looks like the only value is x=0

Answer 5

Because "0" is in the denominator?

Answer 6

no because when x=0 the denominator is undefined. you cannot divide a number by 0

Answer 7

or yes I guess that is what you were asking so yes

Answer 8

Thanks for the help!!

Answer 9

you're welcome