HELP PLEASE! MULTIPLE CHOICE! Write the equations of the asymptotes for the hyperbola represented by 36x^2-y^2-4y=-32.

Question

anonymous · Answer

a. y - 1 = +/- 6 (x - 2)
b. y = +/- 6x
c. y + 2 = +/- 6(x - 1)
d. y + 2 = +/- 6x

anonymous · Answer

@Destinymasha @Loser66

anonymous · Answer

Help me please! I dont understand...

loser66 · Answer

first off, you have to write the expression under the standard form of hyperbola.

loser66 · Answer

which is $$\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$$
then, apply the formula to find out the asymptote which is $$y =\pm\dfrac{-b}{a}$$

anonymous · Answer

Standard form: (((y+2)^2)/(6^2)) - ((x^2)/(1^2)) = 1 @Loser66

anonymous · Answer

Is that right?

loser66 · Answer

Let me check, honestly I didn't work it out. just gave you steps. :)

anonymous · Answer

Ok

loser66 · Answer

yup

loser66 · Answer

but your hyperbola is another form, so that the asymptote will be $y =\pm \dfrac{-a}{b}$where a is the number under "y" term and b is the number under "x" term. Got what I mean?

loser66 · Answer

I am sorry, $y = \pm\dfrac{-a}{b}x$

anonymous · Answer

Ok so the answer is b? @Loser66

loser66 · Answer

yup