Hey guys i need your help
without graphing, determine whether the function represents exponential growth or decay. y=3(1.04)^x
y=2(0.95)^x
y=2(5/3)^x
thanks
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jimthompson5910 (jim_thompson5910):
In general, exponential functions can be written in the form
\[\Large y = a*(b)^x\]
the term 'a' is the starting amount (when x = 0)
The b tells you if you have exponential growth or decay
If b < 1, then you have exponential decay
If b > 1, then you have exponential growth
OpenStudy (anonymous):
so the equation y=3(1.04)^x would be decay?
jimthompson5910 (jim_thompson5910):
what are a and b in the equation y=3(1.04)^x
OpenStudy (anonymous):
a=3 and b=1.04
jimthompson5910 (jim_thompson5910):
now look at the rules I posted for exponential decay and exponential growth
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OpenStudy (anonymous):
oh that's right thank you so much
jimthompson5910 (jim_thompson5910):
you're welcome
OpenStudy (anonymous):
just to make sure here what i got
y=3(1.04)^x would be decay
y=2(0.95)^x= would be growth
y=2(5/3)x= would be decay
if it's wrong can you corrected
jimthompson5910 (jim_thompson5910):
you have it all backwards
jimthompson5910 (jim_thompson5910):
if b = 1.04, then b > 1, so we have growth (not decay)
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