Suppose that y varies inversely with x. Write an equation for the inverse variation. y = 2 when x = 5
\(\Large\color{red}{ \bf y~~varies~~inversely~~with~~x~~means, }\) \(\Large\color{blue}{ \bf y= \frac{k}{x} }\) where x is the constant of variation.
saying that \(\Large\color{blue}{ \bf 2= \frac{k}{5} }\) that gives k=10
\(\Large\color{blue}{ \bf y= \frac{10}{x} }\) would be your equation for any x.
i was just about to say that thanks again i have another one like that if i slove it can you just tell me if im right or wrong please?
y = 2.5 when x = 9 so its k = 22.5; y = 22.5x?
direct or inverse variation ?
inverse variation.
\(\Large\color{blue}{ \bf y= \frac{k}{x} }\) \(\Large\color{blue}{ \bf 2.5= \frac{k}{9} }\) this gives k=22.5 thus you get \(\Large\color{blue}{ \bf y= \frac{22.5}{x} }\)
so im right?
Find the constant of variation k for the inverse variation. Then write an equation for the inverse variation. y = 2.5 when x = 9
the answer is what i just said right?
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